Geometric sequences

1003084910

Level: 
A
We were given a geometric sequence \( \frac12\text{, }\ \frac14\text{, }\ \dots \). What is the formula for the \( n \)th element of the sequence?
\( a_n=\frac1{2^n}\text{, }\ n\in\mathbb{N} \)
\( a_n=\frac1{2^{n+1}}\text{, }\ n\in\mathbb{N} \)
\( a_n=\frac1{2^{n-1}}\text{, }\ n\in\mathbb{N} \)
\( a_n=\frac1{2^{2n}}\text{, }\ n\in\mathbb{N} \)

1003107308

Level: 
A
The first five terms of a geometrical sequence are: \( -2,\ 1,\,-\frac12,\ \frac14,\,-\frac18 \). Find the recursive formula of this sequence.
\( a_1=-2\,;\ a_{n+1}=a_n\cdot\left(-\frac12\right),\ n\in\mathbb{N} \)
\( a_1=-2\,;\ a_{n+1}=a_n\cdot\left(-\frac14\right),\ n\in\mathbb{N} \)
\( a_1=-2\,;\ a_{n+1}=a_n\cdot\frac12,\ n\in\mathbb{N} \)
\( a_1=-2\,;\ a_{n+1}=a_n\cdot\left(-\frac12\right)^n,\ n\in\mathbb{N} \)

1003112803

Level: 
A
The second term of a geometric sequence is \( 24 \) and the fifth term is \( 3 \). Choose the correct formula to find the third term of this sequence.
\( a_3=24\cdot\sqrt[3]{\frac3{24}} \)
\( a_3=24\cdot\sqrt[3]{\frac{24}3} \)
\( a_3=3\cdot\sqrt[3]{\frac3{24}} \)
\( a_3=3\cdot\sqrt[3]{\frac{24}3} \)
\( a_3=8\cdot\sqrt[3]{\frac3{24}} \)

1003124701

Level: 
A
The third term of a geometric sequence is \( 9 \) and the common ratio is \( 3 \). Find the recursive formula of the sequence.
\( a_1=1 \), \( a_{n+1}=3a_n \)
\( a_1=3 \), \( a_{n+1}=a_n+3 \)
\( a_1=9 \), \( a_{n+1}=3a_n \)
\( a_1=3 \), \( a_{n+1}=a_n^2 \)
\( a_1=1\), \(a_{n+1}=\frac13a_n \)

1003124702

Level: 
A
Find the recursive formula of the geometric sequence \( a_n=2\cdot 3^n \), \( n\in\mathbb{N} \).
\( a_1=6 \), \( a_{n+1} = 3a_n \)
\( a_1=2 \), \( a_{n+1} = 3a_n \)
\( a_1=3 \), \( a_{n+1} = 6a_n \)
\( a_1=6 \), \( a_{n+1} = \frac13a_n \)
\( a_1=2 \), \( a_{n+1} = a_n+3 \)